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//Fluid Systems - By - Shiv Kumar
//Chapter 4 - Pelton Turbine (Impulse Turbine)
//Example 4.13
clc
clear
//Given Data:-
H=62; //Effective Head, m
N=225; //Speed of Runner, rpm
P=133.15; //Shaft Power, HP
Ku=0.45; //Speed Ratio
eta_o=86/100; //Overall Efficiency
Cv=0.98;
//Data Used:-
rho=1000; //Density of water, kg/m^3
g=9.81; //Acceleration due to gravity, m/s^2
//Computations:-
P=P*736; //W
Vi=Cv*sqrt(2*g*H); //m/s
u=Ku*sqrt(2*g*H); //m/s
ui=u;
uo=u;
Q=P/(rho*g*H*eta_o); //m^3/s
d=sqrt(Q/((%pi/4)*Vi))*1000; //Diameter of Jet, mm
D=60*u/(%pi*N); //Diameter of Runner, m
//As per designing range, b=3*d to 4*d
b=3.5*d; //Width of Buckets, mm
//As per designing range, b=0.8*d to 1.2*d
T=1.2*d; //Depth of Buckets, mm
Z=round(0.5*D/(d/1000)+15); //Number of Buckets
//Results:-
printf(" (a)Diameter of Jet, d=%.2f mm \n",d) //The answer vary due to round off error
printf(" (b) Diameter of Runner, D=%.3f m \n",D)
printf(" (c) Width of Buckets, b=%.2f mm \n",b) //The answer vary due to round off error
printf(" (d) Depth of Buckets, T=%.2f mm \n",T) //The answer vary due to round off error
printf(" (e) Number of Buckets , Z=%.f \n",Z)
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