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//Fluid system - By - Shiv Kumar
//Chapter 2 - Impact of Jet
//Example 2.33
clc
clear
//Given Data:-
a=0.72; //Total cross-sectional area of Jets, m^2
Vr=12; //Velocity through the Jet relative to ship, m/s
u=6; //Speed of ship, m/s
eta_E=85/100; //Efficiency of I.C. engine
eta_P=70/100; //Efficiency of Centrifugal Pump
Pipe_Loss_per=8; //Percentage of pipe losses (of the kinetic energy of Jet per sec)
//Data Used:-
rho=1000; //Density of water, kg/m^3
//Computations:-
Pipe_Loss=(Pipe_Loss_per/100)*(rho*a*Vr^3/2); //Pipe Losses, N-m/s
V=Vr-u; //Absolute Velocity of the Jet, m/s
//(a)
F=rho*V*a*(V+u); //N
//(b)
W=F*u; //Work done by Jet per second, N-m/s
OE_P=rho*a*Vr^3/2+Pipe_Loss; //Output energy of pump per sec, N-m/s
IP_P=OE_P/eta_P; //Input Energy of pump per sec, N-m/s
OE_E=IP_P; //Output of Engine is equal to Input to the pump
IE_E=OE_E/eta_E; //Input Energy of Engine per sec, N-m/s
eta_o=W/IE_E*100; //Overall Efficiency in percentage
//Results:-
printf("(a)Propelling Force=%.f N \n", F)
printf("(b)Overall Efficiency, eta_o=%.2f percent", eta_o) //The answer vary due to round off error
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