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//Fluid Systems - By Shiv Kumar
//Chapter 16- Hydraulic Power and Its Transmissions
//Example 16.4
//To Find the Diameter of Pipe.
clc
clear
//Given Data:-
l=2100; //Length of the Pipe, m
P=103; //Power Transmitted, kW
pi=392.4; //Pressure at Inlet of Pipe, N/cm^2
eta=80/100; //Efficiency
f=0.005;
//Data Required:-
rho=1000; //Density of Water, Kg/m^3
g=9.81; //Acceleration due to gravity, m/s^2
//Computations:-
H=pi*10^4/(rho*g); //m
hf=H*(1-eta); //m
Q=P*1000/(rho*g*(H-hf)); //m^3/s
d=((64*f*l*Q^2)/(hf*2*g*%pi^2))^(1/5)*1000; //mm
//Results:-
printf("The Diameter of Pipe=%.2f mm\n",d) //The answer vary due to round off error
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