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//Fluid Systems - By Shiv Kumar
//Chapter 12- Reciprocating Pumps
//Example 12.3
//To Calculate The Maximum Speed at which pump may be run and Determine Resultant Suction Head at Begining, Middle and End of the Stroke.
clc
clear
//Given Data:-
D=150; //Diameter of Plunger, mm
L=250; //Stroke length, mm
l_s=10; //Length of Suction Pipe, m
d=75; //Diameter of Suction Pipe, mm
hs=4; //Suction Head, m of water
Ha=10.34; //Atmospheric Pressure, m of water
Habs=2.44; //Absolute Pressure Head, m of water
//Data Used:-
g=9.81; //Acceleration due to gravity, m/s^2
//Computations:-
Hv=Ha-Habs; //Vaccume Pressure, m of water
//For Maximum Resultant Suction Head,
Hs=Hv;
A=(%pi/4)*(D/1000)^2; //m^2
a_s= (%pi/4)*(d/1000)^2; //m^2
r=L/2000; //m
omega=sqrt((Hs-hs)*g*a_s/(l_s*A*r)); //radian/sec
N=60*omega/(2*%pi); //rpm
//Result 1
printf(" The Maximum Speed at which pump may be run, N=%.2f rpm \n",N) //The answer vary due to round off error
//At Begining
Has=(l_s/g)*(A/a_s)*omega^2*r*cosd(0); //m
Hs=hs+Has; //Resultant Head at Begining of Stroke, m of water
//Result 2
printf(" Resultant Head at Begining of Stroke, Hs=%.1f m of water \n",Hs)
//At Middle
Has=(l_s/g)*(A/a_s)*omega^2*r*cosd(90); //m
Hs=hs+Has; //Resultant Head at Middle of Stroke (Has=0), m of water
//Result 3
printf(" Resultant Head at Middle of Stroke, Hs=%.f m of water \n",Hs)
//At the End
Has=(l_s/g)*(A/a_s)*omega^2*r*cosd(180); //m
Hs=hs+Has; //Resultant Head at End of Stroke, m of water
// Resultant Head at End of Stroke is not calculated and displayed as result in the textbook.
//Result 4
printf(" Resultant Head at End of Stroke, Hs=%.1f m of water \n ",Hs)
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