blob: 0cae0067a577aa22dd32b509b6c1e5b2e53fa386 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
|
//Fluid Systems - By - Shiv Kumar
//Chapter 11- Centrifugal Pumps
//Example 11.8
//To Determine the Power Required to drive the centrifugal Pump.
clc
clear
//Given Data:-
Q=40; //Discharge, litres/s
Hst=20; //Static Head, m
D=150; //Diameter of Pipe, mm
L=100; //length of pipe, m
eta_o=70/100; //Overall Efficiency
f=0.015; //Coefficient of friction
//Data Used:-
rho=1000; //Density of water, kg/m^3
g=9.81; //Acceleration due to gravity, m/s^2
//Computations:-
Q=Q/1000; //m^3/s
D=D/1000; //m
A=(%pi/4)*D^2; //m^2
V=Q/A; //m/s
Vd=V;
h_f=4*f*L*V^2/(2*g*D); //Frictional Head Loss in Pipe, m
Hm=Hst+h_f+Vd^2/(2*g); //Manometric Head, m
P=rho*Q*g*Hm/(eta_o*1000); //kW
//Result:-
printf("Power Required to drive the Centrifugal Pump=%.3f kW\n",P) //The answer vary due to round off error
|
