blob: 4697d140a917326781ef9e589c2d47df23a8883a (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
|
//Fluid Systems - By - Shiv Kumar
//Chapter 11 - Centrifugal Pumps
//Example 11.23
//To Find the Head and Impeller Diameter of the other Pump.
clc
clear
//Given Data:-
//For Pump-1,
N1=1000; //Speed, rpm
D1=320; //Impeller Diameter, mm
Hm1=16; //Manometric Head, m
Q1=0.021; //Discharge, m^3/s
//For Pump-2,
N2=1000; //Speed, rpm
//As other Pump has to deliver half the discharge,
Q2=Q1/2; //m^3/s
//Computations:-
Hm2=Hm1*(N2/N1)*sqrt(Q2/Q1); //m
D2=D1*(N1/N2)*sqrt(Hm2/Hm1); //mm
//Results:-
printf("Head of the other Pump(Pump-2), Hm2=%.2f m\n",Hm2)
printf("Impeller Diameter of the other Pump(Pump-2), D2=%.2f mm\n",D2) //The answer vary due to round off error
|
