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//Fluid Systems - By - Shiv Kumar
//Chapter 11 - Centrifugal Pumps
//Example 11.22
clc
clear
//Given Data:-
//For Model,
H_mM=7.5; //Manometric Head, m
Nm=1000; //Speed, rpm
Pm=25; //Shaft Power, kW
//For Prototype,
H_mP=23; //Manometric Head, m
Dm_by_Dp=1/6; //Scale Ratio
//Computations:-
// (a)Working Speed of the Prototype, Np
Np=Nm*Dm_by_Dp*sqrt(H_mP/H_mM); //rpm
// (b)Shaft Power of the Prototype, Pp
Pp=Pm*(Np/Nm)^3*(1/Dm_by_Dp)^5; //kW
// (c)Ratio of Flow Rates handled by the protoytpe and the Model, Qp/Qm
Qp_by_Qm=(Np/Nm)*(1/Dm_by_Dp)^3;
//Results:-
printf(" (a)Working Speed of the Prototype, Np =%.2f rpm\n",Np) //The answer vary due to round off error
printf(" (b)Shaft Power of the Prototype, Pp =%.2f kW\n",Pp) //The answer vary due to round off error
printf(" (c)Ratio of Flow Rates handled by the protoytpe and the Model=%.2f ",Qp_by_Qm) //The answer provided in the textbook is wrong
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