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//Fluid Systems - By - Shiv Kumar
//Chapter 11- Centrifugal Pumps
//Example 11.1
//To Find the Work done by the Impeller on the water per unit weight of water.
clc
clear
//Given Data:-
Di=210; //Internal diameter of Impeller, mm
Do=420; // External diameter of Impeller, mm
N=1100; //speed, rpm
beta_i=20; //Vane Angle at Inlet, degrees
beta_o=30; //Vane Angle at Outlet, degrees
//As water enters the impeller radially,
alpha_i=90; //degrees
//Data Used:-
g=9.81; //Acceleration due to gravity, m/s^2
//Computations:-
Di=Di/1000; //m
Do=Do/1000; //m
ui=%pi*Di*N/60; //m/s
uo=%pi*Do*N/60; //m/s
Vfi=ui*tand(beta_i); //m/s
Vfo=Vfi;
Vwo=uo-Vfo/tand(beta_o); //m/s
Work=Vwo*uo/g; //N-m/N
//Result:-
printf(" The Work done by the Impeller on the water per unit weight of water =%.2f N-m/N \n",Work) //The answer vary due to round off error
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