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//Chapter 5, Example 5.4, page 192
clc
//Initialisation
f=0.5 //frequency in MHz
Pa=100 //transmitter power
Po=1000
e120=68 //from figure 5.10
e220=85 //from figure 5.9
e230=80
e330=60 //from figure 5.10
e380=48
e350=50 //from figure 5.10
e250=75 //from figure 5.9
e260=73
e160=60 //from figure 5.10
e180=48
//Calculation
ETR=e120-e220+e230-e330+e380
ERT=e350-e250+e260-e160+e180 //The answer provided in the textbook is wrong
ER=(ETR+ERT)/2 //The answer provided in the textbook is wrong
Ea=ER+(10*log10(Pa*Po**-1))
lb=137.2+(20*log10(f))-ER
//Results
printf("(1) Electric field = %.1f dB",Ea) //The answer provided in the textbook is wrong
printf("\n(2) Basic loss path = %.1f dB",lb) //The answer provided in the textbook is wrong
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