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//Chapter 4, Example 4.9, page 158
clc
//Initialisation
phi=166 //in radian
pi=3.14
t=35*pi/180 //geographic latitude in radian
t1=60*pi/180 //zenith angle in radian
N=80*pi/180 //in radian
x=92
y=35
h=35
p=1.2
//Calculation
m=0.11-0.49*cos(t)
fe=0.004*(1+0.021*166)**2 //minimum value of f0E
A=1+0.0094*(phi-66) //A value
B=(cos(N))
B1=B**m //B value
C=x+y*cos(t) //C value
D=cos(t1)**p //D value
F=(A*B*C*D)**(0.25) //exact value of f0E
//Results
printf("(1) Minimum value of f0E = %.2f x 10^-2 MHz",(fe*100))
printf("\n(2) f0E = %.2f MHz",F) //The answer provided in the textbook is wrong
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