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//Chapter 4: Selection of Motor Power Rating
//Example 5
clc;
//Variable Initialization
P=100 //Half hour rating of the motor
Cr=80 //Heating time constant in minutes
n=0.7 //Maximum efficiency at full load
//Solution
Pcu=n**2 //Coppper loss
a=Pcu
K=sqrt((1+a)/(1-%e**(-30/Cr))-a)
Pco=P/K
mprintf("Therefore the continuous rating is:%.2f kW",Pco)
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