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//Chapter 10:Traction Drives
//Example 6
clc;
//Variable Initialization
G=10 //up gradient of the locomotive
Ml=110 //weight of the locomotive coach in tonne
Mt=500 //weight of the train in tonne
r=35 //train resistance N/tonne
n=0.8 //80% of the locomotive weight is carried by the driving wheels
alpha=1 //acelaration in kmphps
//Solution
//when only the 110 tonne locomotive is present
Md=Ml*n //weight of the motor
M=Mt+Ml //total mass of the train
Me=1.1*M
Ft=277.8*Me*alpha+9.81*M*G+M*r //total tractive effort required to move the train
Fm=Ft
u=Fm/(9810*Md) //co-efficient of adhesion ,since Fm=9810*u*Md
//when another locomotive of 70 is added together
Md=Ml*n+70 // mass of the motor
M_=Mt+Ml+70 // mass of the train
Fm=9810*u*Md
Ft=Fm
M=Ft/(277.8*1.1*alpha+9.81*G+r) //total mass of the train, since Ft=277.8*Me*alpha+9.81*M*G+M*r
W=M-M_ //weight of additional bogies to be attached
//Results
mprintf("\n Given co-efficient of adhesion is: %.2f",u)
mprintf("\n Weight of additional bogies to be attached is:%.1f T",W)
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