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//Chapter 10:Traction Drives
//Example 1
clc;
//Variable Initialization
Ma=480 //mass of each motor armature in kg 0.48tonne=480kg
Da=0.5 //average diameter of each motor in m
m=450 //mass of each wheel in kg
R=0.54 //radius of each wheel tread in m
M=40 //combine wight of one motor and one trailer coach in ton
alpha=5 //accelaration in metres per second
N=4 //number of DC motors
a=0.4 //gear ratio
r=20 //train resistance in ohms
//Solution
Jw=1/2*m*R**2 //inertia of the each wheel in kg metre square
nw=2*(N*2) //total number of wheels
J1=nw*Jw //total inertia of all the wheels in kg metre square
Jm=N*(1/2*Ma*(Da/2)**2) //approximate inertia of all the motors in kg metre square
J2=Jm/a**2 //approximate innertia of the motor referred to the wheels in kg metre square
Fa2=(J1+J2)*alpha*1000/3600/R //Tractive efforts for driving rorating parts
Fa1=277.8*M*alpha //tractive efforts to accelerate the train mass horizontally
Fr=r*M //Tractive efforts required to overcome train resistance
Ft=Fa1+Fa2+Fr //Tractive efforts required to move the train
Tm=a*R*Ft/N //torque per motor
//Result
mprintf("\nTorque per motor: %.1f N-m",Tm)
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