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//Chapter 6: Electrochemistry
//Problem: 8
clc;
//Declaration of Constant
F = 96500 //in C per mol
//Declaration of Variables
E1o = - 2.48 //in V
E2o = 1.61 //in V
// Solution
delta_G1 = - 3 * F * (- 2.48)
delta_G2 = - 1 * F * 1.61
mprintf("delta_G3 = delta_G1 + delta_G2\n")
mprintf(" delta_G3 = - 4 * F * E3o\n")
E3o = (delta_G1 + delta_G2) / (- 4 * F)
mprintf(" The reduction potential for the half-cell Pt/Ce, Ce+4 is %.4f V",E3o)
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