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//Chapter 3: Thermodynamic and Chemical Equilibrium
//Problem: 7
clc;
//Declaration of Constant
d_h_vap = 2.0723 // kJ per g
Tb = 373 // K
// Solution
d_h_vap = d_h_vap * 18 // kJ per mol
d_s = d_h_vap / Tb
d_g = d_h_vap - Tb * d_s
d_s = d_s * 1000
mprintf("The Entropy change is: %.1f J / mol / K\n",d_s)
mprintf(" The Free Energy change is:%d kJ/mol", d_g)
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