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//Chapter 3: Thermodynamic and Chemical Equilibrium
//Problem: 23
clc;
//Declaration of Variables
Ti = 25 // C
S = 0.00179 // g / L
// Solution
S =S / 170 // mol / L
Ksp = S ** 2
mprintf("Solubility product at 25 C is %.4e mol square L square",Ksp)
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