blob: 35b67c388f75755fdf7ecf4f68f6e2ed34ae9d69 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
|
//Chapter 3: Thermodynamic and Chemical Equilibrium
//Problem: 21
clc;
//Declaration of Variables
Kc = 0.5 // mole square litre square
T = 400 // K
R = 0.082 // litre atm per degree per mole
// Solution
Kp = Kc * (R * T) ** (-2)
mprintf("The given equilibrium is\n")
mprintf(" N2(g) + 3H2(g) <--> 2NH3(g)\n")
mprintf(" Kp is %.3e",Kp)
|
