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//Chapter 3: Thermodynamic and Chemical Equilibrium
//Problem: 13
clc;
//Declaration of Constants
l_v = 101 //in cal /g, Latent headt of vap.
mwt = 78 // molecular weight of benzene
//Declaration of Variable
m = 2
Tb = 80.2 // C, boiling point of benzene
// Solution
Tb = Tb + 273 // K
d_h = l_v * mwt
d_s = d_h / Tb
d_g = d_h - Tb * d_s
mprintf("d_s = %.2f cal / K\n",d_s)
mprintf(" d_g = d_a = %d", d_g)
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