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//Chapter 15: Environmental Pollution and Control
//Problem: 2
clc;
//Declaration of Variables
v0 = 30 // cm cube, effluent
v1 = 9.8 // cm cube, K2Cr2O7
M = 0.001 // M, K2Cr2O7
// Solution
Oeff = 6 * 8 * v1 * M
mprintf("30 cm cube of effluent contains =:%.4f mg of O2\n",Oeff)
cod = Oeff * 1000 / 30.
mprintf(" 1l of the effluent requires %.2f mg of O2\n",cod)
mprintf(" COD of the effluent sample=%.2f ppm",cod)
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