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//Chapter 14: Water Treatment
//Problem: 9
clc;
//Given Constants For Specific Elements
Fe = 56
S = 32
O = 16
//Solution
hardness = Fe + S + O * 4
hardn= (hardness * 215 )/100
mprintf("215 ppm of hardness is : %.1f ppm of FeSO4",hardn)
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