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//Chapter 13: Fuel and Combustions
//Problem: 7
clc;
// Solution
wt_O = 2 * 32 / 12.0
wt_a = wt_O * 100 / 23.2
vol_a = wt_a / 28.94 * 22.4
mprintf("Volume of air needed for the complete combustion of 2kg coke is %.3f litres at NTP",vol_a)
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