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//Chapter 13: Fuel and Combustions
//Problem: 5
clc;
//Declaration of Variables
V = 0.1 // metre cube
W = 25 // kg
t1 = 20 // C
t2 = 33 // C
m = 0.025 // kg
// Solution
HCV = W * (t2 - t1) / V
LCV = HCV - (m / V) * 580
mprintf("HCV is %d kcal / metre cube\n", HCV)
mprintf(" LCV is %d kcal / metre cube", LCV)
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