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//Chapter 13: Fuel and Combustions
//Problem: 3
clc;
//Declaration of Variables
x = 0.72 // g
W = 250 // g
w = 150 // g
t1 = 27.3 // C
t2 = 29.1 // C
// Solution
HCV = ((W + w) * (t2 - t1)) / x
HCV = HCV * 4185.0 / 10 ** 6
mprintf("HCV of fuel is : %.3f KJ / Kg",HCV)
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