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//Chapter 13: Fuel and Combustions
//Problem: 14
clc;
//Declaration of Variables
C = 80 // %
H = 7 // %
N = 2.1 // %
O = 3 // %
S = 3.5 // %
Ash = 4.4 // %
// Solution
HCV = 1 / 100. * (8080 * C + 34500 * (H - O / 8.) + 2240 * S)
LCV = HCV - 0.09 * H * 587
mprintf("HCV is %d kcal/kg\n",HCV)
mprintf(" LCV is %d kcal/kg",LCV)
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