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//Chapter 13: Fuel and Combustions
//Problem: 12
clc;
//Declaration of Variables
C = 750 // g
H = 52 // g
O = 121 // g
N = 32 // g
ash = 45 // g
// Solution
min_wt_a = (C * 32 / 12. + H * 16 / 2. - O) * 100 / 23.
HCV = 1 / 1000. * (8080 * C + 34500 * (H - O / 8.) + 2240 * 0)
LCV = HCV - 0.09 * H * 587 / 10.0
mprintf("HCV is %d kcal/kg\n",HCV)
mprintf(" LCV is %d kcal/kg",LCV)
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