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////Given
lembda=6.2*10**-6
W=0.1 //ev
h=6.6*10**-34 //Js
c=3*10**8 //m/s
e=1.6*10**-19
//Calculation
E=((h*c)/(lembda*e))-W
//Result
printf("\n Maximum kinetic energy of photoelectron %0.1f ev",E)
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