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////Given
lembda=6.2*10**-6
W=0.1                                          //ev
h=6.6*10**-34                                  //Js
c=3*10**8                                      //m/s
e=1.6*10**-19

//Calculation
E=((h*c)/(lembda*e))-W

//Result
printf("\n Maximum kinetic energy of photoelectron  %0.1f ev",E)