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////Given
lembda=6800.0*10**-10 //m
h=6.6*10**-34
W=2.3 //ev
c=3*10**8 //m/s
//Calculation
E=((h*c)/lembda)/1.6*10**-19
//Result
printf("\n Energy is %0.2f ev",E*10**38)
printf("\n since the energy of incident photon is less then the work function of Na, photoelecrticemession is not possible with the given light.")
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