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////given
h=6.62*10**-34 //Js
c=3*10**8 //m/s
lembda=4560.0*10**-10 //m
p=1*10**-3 //W
a=0.5/100
e=1.6*10**-19
//calculation
E=(h*c)/lembda
N=p/E //Number of photons incedent on the surface
n=N*a
I=n*e
//result
printf("\n Photoelectric current %0.2f *10**-6 A",I*10**6)
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