blob: 008edd6c0657937b72c6ff0cdeda39b33b786063 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
|
// Exa 7.7
clc;
clear;
// Given data
fH= 400; // Higher cutoff frequency(Hz)
fL=2000; // lower cutoff frequency(Hz)
Ao=2; // Pass band gain
// Solution
disp("For HPF, fL=2 kHz.");
disp("Assume C2=0.1 μF. ");
C2=0.1*10^-6; // Farads
// Since fL= 1/(2*%pi*R*C2);
// Therefore
RL= 1/(2*%pi*C2*fL);
printf(' The calculated value of R = %d Ω.',int(RL));
printf('\n Let R = 800 Ω.');
// Since Ao=Ao2 = 1+ (Rf/Ri);
disp("Let Rf = Ri =10 kΩ(say) to give A02 of 2.");
disp("");
disp("");
disp("For LPF, fL=400 Hz.");
disp("Assume C1=0.1 μF. ");
C1=0.1*10^-6; // Farads
// Since fH= 1/(2*%pi*R*C1);
// Therefore
RF= 1/(2*%pi*C1*fH);
printf(' The calculated value of R = %d Ω.',int(RF));
printf('\n Let R = 4 kΩ.');..
// Since Ao=Ao1 = 1+ (Rf/Ri);
disp("Let Rf = Ri =10 kΩ(say) to give A01 of 2.");
disp("");
disp("");
disp("The schematic arrangement and the frequency response is shown in figs. 7.16(a,b) on page no. 280.")
|
