3673/CH3/EX3.a.1/Example_a_3_1.sce


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//Example 3_1 page no:129
clc;
V=(10/2.92)/((1/4.31)+(1/6.77)+(1/2.92));
Va=V*(2/(2+2.31));
Vb=V*(6/6.77);
Vab=Va-Vb;
disp(Vab,"the voltage across Vab is (in V)");