3673/CH2/EX2.16/Ex2_16.sce


1
2
3
4
5
6

//Example 2_16 page no:84
clc
current_source=5//in ampere
source_resistance=5//in ohm
equ_src_volt=current_source*source_resistance
disp(equ_src_volt,"equivalent source voltage is (in volt)")