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//Example 1_2 page no:21
clc;
I8=20/8;
I15=(2.5*11)/(11+28);
V28=0.71*28;
V19=2.5*19;
emf=V28+V19;//calculating the emf
disp(I8,"the current flowing through 8 ohm resistor is (in A)");
disp(I15,"the current flowing through 15 ohm resistor is (in A)");
disp(V28,"the voltage across 28 ohm resistor is (in V)");
disp(V19,"the voltage across 19 ohm resistor is (in V)");
disp(emf,"the emf of the battery is (in V)");
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