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//Variable declaration
N=6.023*10**26
deltaHv=120
B=1.38*10**-23
k=6.023*10**23
//Calculations
n0=0 // 0 in denominator
n300=N*exp(-deltaHv*10**3/(k*B*300)) //The number of vacancies per kilomole of copper
n900=N*exp(-(deltaHv*10**3)/(k*B*900))
//Results
printf('at 0K, The number of vacancies per kilomole of copper is %0.3f' ,n0)
printf('at 300K, The number of vacancies per kilomole of copper is %0.3f *10**5\n',(n300/10**5))
printf('at 900K, The numb ber of vacancies per kilomole of copper is %0.3f *10**19\n',(n900/10**19))
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