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// Example 5.13
// Determine the expected in-rush current
// Page No. 208
clc;
clear;
close;
// Given data
kva1=5.6; // KVA/hp lower limit from table 5.9
hp=150; // Motor horsepower
Vline=460; // Line voltage
kva2=6.3; // KVA/hp upper limit from table 5.9
// Expected in-rush current
// Lower limit of expected range of in-rush current is
Ilrss=(kva1*hp*1000)/(sqrt(3)*Vline);
// Upper limit of expected range of in-rush current is
Iulss=(kva2*hp*1000)/(sqrt(3)*Vline);
// Display result on command window
printf("\n Lower limit of expected range of in-rush current = %0.0f A",Ilrss);
printf("\n Upper limit of expected range of in-rush current = %0.0f A",Iulss);
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