blob: 411fda2eaf11f17fa7f4c6d094b648e44d1da810 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
|
// Example 2.13
// Determine (a) Efficiency at rated load and 80% power factor
// (b) 70% load and 80% power factor
// Page No. 75
clc;
clear;
close;
// Given data
FP=0.80; // Power factor
PcorePU=0.0045; // Percentage core loss
RPU=0.0146; // Percentage resistance
Sload=70; // 70% rated load
Srated=100; // 100% rated load
// (a) Efficiency at rated load and 80% power factor
etarated=FP/(FP+RPU+PcorePU);
// (b) Efficiency at 70% load and 80% power factor
SPU=Sload/Srated;
IPU=SPU; // I_load is proportional to S_load
eta=(SPU*FP)/(SPU*FP+PcorePU+IPU^2*RPU) // Efficiency
// Display result on command window
printf("\n Efficiency at rated load = %0.3f ", etarated);
printf("\n Efficiency at 70 percent load = %0.3f ",eta);
disp('There is very little change in efficiency');
|
