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clc
// Fundamental of Electric Circuit
// Charles K. Alexander and Matthew N.O Sadiku
// Mc Graw Hill of New York
// 5th Edition
// Part 1 : DC Circuits
// Chapter 3: Methods of Analysis
// Example 3 - 8
clear; clc; close;
//
// Given data
// Diagonal term of G
G11 = (1/5.00) + (1/10.00);
G22 = (1/5.00) + (1/8.00) + (1/1.00);
G33 = (1/8.00) + (1/8.00) + (1/4.00);
G44 = (1/8.00) + (1/2.00) + (1.00);
// Off Diagonal term of G
G12 = (-1/5.00); G13 = 0.00; G14 = 0.00;
G21 = -0.20; G23 = -1/8.00; G24 = -1.00;
G31 = G13; G32 = G23; G34 = -0.1250;
G41 = G14; G42 = G24; G43 = G34;
// Input Current
I1 = -3.00;
I2 = -3.00;
I3 = 0.00;
I4 = 6.00;
//
// Calculations
// Calculations V1, V2, V3 and V4
G = [ G11 G12 G13 G14;
G21 G22 G23 G24;
G31 G32 G33 G34;
G41 G42 G43 G44];
I = [ I1; I2; I3; I4];
V = inv(G)*I
//
// Display the result
disp("Example 3-8 Solution : ");
printf(" \n V1 = Voltage for Node 1 = %.3f Volt",V(1))
printf(" \n V2 = Voltage for Node 2 = %.3f Volt",V(2))
printf(" \n V3 = Voltage for Node 3 = %.3f Volt",V(3))
printf(" \n V4 = Voltage for Node 4 = %.3f Volt",V(4))
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