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clc
// Fundamental of Electric Circuit
// Charles K. Alexander and Matthew N.O Sadiku
// Mc Graw Hill of New York
// 5th Edition
// Part 2 : AC Circuits
// Chapter 14 : Frequency Response
// Example 14 - 19
clear; clc; close;
//
// Given data
fc = 2500.0000;
R1 = 6.0000;
R2 = R1;
//
// Calculations C for Highpass Filter
C = 1/(2*%pi*fc*R1)
// Calculations L for Lowpass Filter
L = R2/(2*%pi*fc)
//
disp("Example 14-19 Solution : ");
printf(" \n C = Capacitance of Capacitor = %.3f mikroFarad",C*10^6)
printf(" \n L = Inductance of Inductor = %.3f mikrohenry",L*10^6)
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