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clc
// Fundamental of Electric Circuit
// Charles K. Alexander and Matthew N.O Sadiku
// Mc Graw Hill of New York
// 5th Edition
// Part 2 : AC Circuits
// Chapter 14 : Frequency Response
// Example 14 - 18
clear; clc; close;
//
// Given data
f0 = 770.0000;
f1 = 697.0000;
f2 = 852.0000;
R = 600.0000;
//
// Calculations Bandwidth
B = 2*%pi*(f2 - f1);
// Calculations L
L = R/B;
// Calculation C
C = 1/(4*(%pi)^2*(f0)^2*L);
//
disp("Example 14-18 Solution : ");
printf(" \n C = Capacitance of Capacitor = %.3f nanoFarad",C*10^9)
printf(" \n L = Inductance of Inductor = %.3f Henry",L)
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