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clc
// Fundamental of Electric Circuit
// Charles K. Alexander and Matthew N.O Sadiku
// Mc Graw Hill of New York
// 5th Edition
// Part 2 : AC Circuits
// Chapter 14 : Frequency Response
// Example 14 - 11
clear; clc; close;
//
// Given data
fb = 100.0000;
fo = 200.0000;
R = 150.0000;
//
// Calculations Inductance of Inductor
B = 2*%pi*fb;
L = R/B
// Calculations Capacitance of Capacitor
Wo = 2 * %pi * fo
C = 1/((Wo^2)*L)
//
disp("Example 14-12 Solution : ");
printf(" \n L = Inductance of Inductor = %.3f H",L)
printf(" \n C = Capacitance of Capacitor = %.3f mikro - Farad",C*10^6)
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