1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
|
clc
// Fundamental of Electric Circuit
// Charles K. Alexander and Matthew N.O Sadiku
// Mc Graw Hill of New York
// 5th Edition
// Part 2 : AC Circuits
// Chapter 12 : Three Phase Circuit
// Example 12 - 5
clear; clc; close; // Clear the work space and console.
//
// Given data
Vab_mag = 210.0000;
Vab_angle = 0.0000;
ZY = complex(40,25);
//
// Calculations Phase Voltage (Van)
Van_mag = Vab_mag/(3)^0.5
Van_angle = -30.0000;
// Calculatioan Line Current a
I_a_mag = Van_mag/norm(ZY)
ZY_real = real(ZY)
ZY_imag = imag(ZY)
ZY_angle = atand(ZY_imag,ZY_real)
I_a_angle = Van_angle - ZY_angle
// Calculations Line Current b
I_b_mag = I_a_mag;
I_b_angle = -120.0000 + I_a_angle;
// Calculations Line Current c
I_c_mag = I_a_mag;
I_c_angle = 120.0000 + I_a_angle;
// Calculations Phase Current AB
I_AB_mag = I_a_mag;
I_AB_angle = I_a_angle;
// Calculations Phase Current BC
I_BC_mag = I_b_mag;
I_BC_angle = I_b_angle;
// Calculations Phase Current CA
I_CA_mag = I_c_mag;
I_CA_angle = I_c_angle;
//
disp("Example 12-5 Solution : ");
printf(" \n I_AB_mag = Magnitude of Phase Currents AB = %.3f A",I_AB_mag)
printf(" \n I_AB_angle = Angle of Phase Current AB = %.3f Degree",I_AB_angle)
printf(" \n I_BC_mag = Magnitude of Phase Currents BC = %.3f A",I_BC_mag)
printf(" \n I_BC_angle = Angle of Phase Current BC = %.3f Degree",I_BC_angle)
printf(" \n I_CA_mag = Magnitude of Phase Currents CA = %.3f A",I_CA_mag)
printf(" \n I_CA_angle = Angle of Phase Current CA = %.3f Degree",I_CA_angle)
printf(" \n I_a_mag = Magnitude of Line Currents a = %.3f A",I_a_mag)
printf(" \n I_a_angle = Angle of Line Current a = %.3f Degree",I_a_angle)
printf(" \n I_b_mag = Magnitude of Line Current b = %.3f A",I_b_mag)
printf(" \n I_b_angle = Angle of Line Current b = %.3f Degree",I_b_angle)
printf(" \n I_c_mag = Magnitude of Line Currents c = %.3f A",I_c_mag)
printf(" \n I_c_angle = Angle of Line Current c = %.3f Degree",I_c_angle)
|
