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clc
// Fundamental of Electric Circuit
// Charles K. Alexander and Matthew N.O Sadiku
// Mc Graw Hill of New York
// 5th Edition
// Part 2 : AC Circuits
// Chapter 12 : Three Phase Circuit
// Example 12 - 3
clear; clc; close;
//
// Given data
Van_mag = 100.0000;
Van_angle = 10.0000;
Zdelta = complex(8,4);
//
// Calculations Line Voltage (Vab)
Vab_mag = (3)^0.5 * Van_mag
Vab_angle = Van_angle + 30.0000;
// Calculatioan Phase Current AB
I_AB_mag = Vab_mag/norm(Zdelta)
Zdelta_real = real(Zdelta)
Zdelta_imag = imag(Zdelta)
Zdelta_angle = atand(Zdelta_imag,Zdelta_real)
I_AB_angle = Vab_angle - Zdelta_angle
// Calculations Phase Current BC
I_BC_mag = I_AB_mag;
I_BC_angle = -120.0000 + I_AB_angle;
// Calculations Phase Current CA
I_CA_mag = I_AB_mag;
I_CA_angle = 120.0000 + I_AB_angle;
// Calculations Line Current a
I_a_mag = (3)^0.5 * I_AB_mag;
I_a_angle = -30.0000 + I_AB_angle;
// Calculations Line Current b
I_b_mag = I_a_mag;
I_b_angle = -120.0000 + I_a_angle;
// Calculations Line Current c
I_c_mag = I_a_mag;
I_c_angle = 120.0000 + I_a_angle;
//
disp("Example 12-3 Solution : ");
printf(" \n I_AB_mag = Magnitude of Phase Currents AB = %.3f A",I_AB_mag)
printf(" \n I_AB_angle = Angle of Phase Current AB = %.3f Degree",I_AB_angle)
printf(" \n I_BC_mag = Magnitude of Phase Currents BC = %.3f A",I_BC_mag)
printf(" \n I_BC_angle = Angle of Phase Current BC = %.3f Degree",I_BC_angle)
printf(" \n I_CA_mag = Magnitude of Phase Currents CA = %.3f A",I_CA_mag)
printf(" \n I_CA_angle = Angle of Phase Current CA = %.3f Degree",I_CA_angle)
printf(" \n I_a_mag = Magnitude of Line Currents a = %.3f A",I_a_mag)
printf(" \n I_a_angle = Angle of Line Current a = %.3f Degree",I_a_angle)
printf(" \n I_b_mag = Magnitude of Line Current b = %.3f A",I_b_mag)
printf(" \n I_b_angle = Angle of Line Current b = %.3f Degree",I_b_angle)
printf(" \n I_c_mag = Magnitude of Line Currents c = %.3f A",I_c_mag)
printf(" \n I_c_angle = Angle of Line Current c = %.3f Degree",I_c_angle)
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