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// Exa 5.2
clc;
clear all;
// Given data
// With reference to data given in Exa 5.1
ei=1; // Applied input voltage to integrator(V)
t1=1; // sec
// Given data
er=5;// Reference voltage applied at time t1 to integrator(V)
// Solution
// Using equation 5.3 from page no. 118
t2=ei/er * t1;// Time interval t2(sec)
printf(' The time interval of t2 is = %.1f sec \n',t2);
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