blob: 03a3a4fd852d666520121ed88db11808196cacba (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
|
// Exa 13.6
clc;
clear all;
// Given data
K=0.32; // Coupling co efficient
Op=1;// Output in oz.in.
// Solution
// 1 oz.in.= 1 oz.in. * (1 ft/12 in.) * (1 lb/16 oz) * (1.3561/1 ft lb) = 7.06*10^-3 J ;
Elec_mech= 7.06*10^-3; // Electrical energy converted to mechanical energy(J)
Ee=Elec_mech/K; // Applied Electrical energy
printf(' The electrical energy of %.2f mJ must be applied \n',Ee*10^3);
// The answer mentioned in the book is incorrect
|
