blob: 760f073957682bc4245cb9327ff174861be63fc0 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
|
// Example 6.9
// Calculation of the variance of the signal–ASE beat noise current.
// Page no 290
clc;
clear;
close;
//Given data
si=30; // Electrical SNRs at the amplifier input
so=25; // Electrical SNRs at the amplifier output
p=0; // Signal power at output
r=-126; // Signal power at input
R=0.9; // Planck constant
f=195*10^12; // Frequency
b=20*10^9; // Bandwidth
// The variance of the signal–ASE beat noise current
p1=10^(p/10)*10^-3;
rn=10^(r/10)*10^-3;
r1=rn*b;
r0=2*R^2*p1*r1;
//Displaying results in the command window
printf("\n The variance of the signal–ASE beat noise current = %0.2f x 10^-9 A^2 W/Hz",r0*10^9);
// The value of noise power given in example as -126 but for calculation it is taken as -128 in book. Therefore answer is varying.
|
