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// Example no.3.10
// To calculate the effective mass of the electron in the valence band.
// Page no.134
clc;
clear;
// Given data
Eg=1.18; // Band gap in eV
Eg=1.18*1.602*10^-19; // Band gap in J
hk1=9*10^-26; // The crystal momentum in Kg.m/s
h=1.054*10^(-34); // The distance between two levels
f=3.94*10^14; // Light wave of frequency
m=9.109*10^(-31); // The electron rest mass in kg
mr=(hk1)^2/(2*(h*2*%pi*f-Eg)); // The reduced mass in kg
meff1=0.07*m; // The effective mass of an electron in the conduction band
// The effective mass of the electron in the valence band.
meff2=(mr*meff1)/(meff1-mr); // The effective mass of the electron in the valence band.
// Displaying the result in command window
printf('\n The effective mass of the electron in the valence band = %0.2f X 10^-31 kg',meff2*10^31);
// The answer is varrying due to round-off error
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