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// Example 11.1
// Calculation of the minimum number of taps needed to compensate for the fiber dispersion
// Page no 509
clc;
clear;
close;
// Given data
b=22*10^-27; // Power launched in port 1
l=800*10^3; // Power launched in port 2
T=50*10^-12; // Power launched in port 3
// Bit rate of communication system
k=ceil((%pi*b*l)/T^2);
n=(2*k)+1;
// Displaying results in the command window
printf("\n The number of the taps = %0.3f ",n);
// The answers vary due to round off error
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