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// Example 3.5
// To find number of users for a)system A b)system B c)system C
// Page No.83
clc;
clear;
// Given data
GOS=0.02; // Grade of Service (Probability of bloacking)
lamda=2; // Average calls per hour
H=(3/60); // Call duration in seconds
Au=lamda*H; // Traffic intensity per user
// a)To find number of users for System A
C1=19; // Number of channels used
A1=12; // Traffic intensity from Erlang B chart
U1=round(A1/Au); // Number of users per cell
cells1=394;
TU1=U1*cells1; // Total number of users
MP1=TU1/(2*10^6)*100; // Market penetration percentage
// b)To find number of users for System B
C2=57; // No. of channels used
A2=45; // Traffic intensity from Erlang B chart
U2=round(A2/Au); // Number of users per cell
cells2=98;
TU2=U2*cells2; // Total no. of users
MP2=TU2/(2*10^6)*100; // Market penetration percentage
// c)To find number of users for System C
C3=100; // Number of channels used
A3=88; // traffic intensity from Erlang B chart
U3=round(A3/Au); // Number of users per cell
cells3=49;
TU3=U3*cells3; // Total no. of users
MP3=TU3/(2*10^6)*100; // Market penetration percentage
TU=TU1+TU2+TU3; // Total number of users in all 3 systems
MP=TU/(2*10^6)*100; // Combined Market penetration percentage
// Displaying the result in command window
printf('\n Total number of users in system A = %0.0f',TU1);
printf('\n The percentage market penetration of system A = %0.2f',MP1);
printf('\n \n Total number of users in system B = %0.0f',TU2);
printf('\n The percentage market penetration of system B = %0.3f',MP2);
printf('\n \n Total number of users in system C = %0.0f',TU3);
printf('\n The percentage market penetration of system C = %0.3f',MP3);
printf('\n \n Total number of users in all 3 systems = %0.0f',TU);
printf('\n The combined Market penetration percentage of all systems = %0.3f',MP);
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