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// Example 3.2
// To find frequency reuse factor for path loss exponent (n) a)n=4 b)n=3
// Page No.72
clc;
clear;
// Given data
SIdB=15; // Signal to interference(dB)
io=6; // Number of cochannel cell
// For n=4
n1=4; // Path loss exponent
N1=7; // First consideration: frequency reuse factor N=7
DR1=sqrt(3*N1); // Co-channel reuse ratio
si1=(1/io)*(DR1)^n1; // Signal to interference
sidB1=10*log10(si1); // Signal to interference(dB)
// For n=3
n2=3; // Path loss exmponent
si=(1/io)*(DR1)^n2; // Signal to interference for first consideration: frequency reuse factor N=7
sidB=10*log10(si); // Signal to interference(dB)
N2=12; // second consideration : frequency reuse factor N=12 since sidB<SIdB
DR2=sqrt(3*N2); // Co-channel reuse ratio
si2=(1/io)*(DR2)^n2; // Signal to interference
sidB2=10*log10(si2); // Signal to interference(dB)
// Displaying the result in command window
printf('\n Signal to noise ratio for n=4 with frequency reuse factor N=7 = %0.2f dB',sidB1);
printf('\n Signal to noise ratio for n=3 with frequency reuse factor N=7 = %0.2f dB',sidB);
printf('\n Signal to noise ratio for n=3 with frequency reuse factor N=12 = %0.2f dB',sidB2);
printf('\n Since SIR is for n=3 with frequency reuse factor N=7 greater than the minimum required, so N=12 is used.');
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