path: root/3535/CH10/EX10.4/Ex10_4.sce

//Chapter 10, Example 10.4, Page 283
clc
clear
// k of a homogeneous
f = 687/(687 +(0.0034*40000))
k = 2.07*f
printf("f = %f \n",f)
printf(" k = %f \n",k)
//Answer may vary due to round off error