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// A Texbook on POWER SYSTEM ENGINEERING
// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
// DHANPAT RAI & Co.
// SECOND EDITION
// PART II : TRANSMISSION AND DISTRIBUTION
// CHAPTER 2: CONSTANTS OF OVERHEAD TRANSMISSION LINES
// EXAMPLE : 2.18 :
// Page number 115
clear ; clc ; close ; // Clear the work space and console
// Given data
d = 2.0/100 // Diameter of conductor(m)
D_AB = 4.0 // Spacing between conductor A & B(m)
D_BC = 4.0 // Spacing between conductor B & C(m)
D_CA = 8.0 // Spacing between conductor C & A(m)
// Calculations
r = d/2 // Radius of conductor(m)
e = 1.0/(36*%pi)*10**-9 // Constant ε_0
D_eq = (D_AB*D_BC*D_CA)**(1.0/3) // Equivalent distance(m)
C_n = 2*%pi*e/log(D_eq/r)*1000.0 // Capacitance to neutral(F/km)
C_nu = C_n*10.0**6 // Capacitance to neutral(μF/km)
// Results
disp("PART II - EXAMPLE : 2.18 : SOLUTION :-")
printf("\nNew value of capacitance, C_n = %.5f μF/km \n", C_nu)
printf("\nNOTE: Changes in the obtained answer from that of textbook is due to more approximation in the textbook")
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